4x^2y(x+1)+8x(x+1)=0

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Solution for 4x^2y(x+1)+8x(x+1)=0 equation:


Simplifying
4x2y(x + 1) + 8x(x + 1) = 0

Reorder the terms:
4x2y(1 + x) + 8x(x + 1) = 0
(1 * 4x2y + x * 4x2y) + 8x(x + 1) = 0
(4x2y + 4x3y) + 8x(x + 1) = 0

Reorder the terms:
4x2y + 4x3y + 8x(1 + x) = 0
4x2y + 4x3y + (1 * 8x + x * 8x) = 0
4x2y + 4x3y + (8x + 8x2) = 0

Reorder the terms:
8x + 8x2 + 4x2y + 4x3y = 0

Solving
8x + 8x2 + 4x2y + 4x3y = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '4x'.
4x(2 + 2x + xy + x2y) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(2 + 2x + xy + x2y)' equal to zero and attempt to solve: Simplifying 2 + 2x + xy + x2y = 0 Solving 2 + 2x + xy + x2y = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Solution

x = {0}

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